Sort by

recency

|

3 Discussions

|

  • + 0 comments

    C++ solution

    #include <bits/stdc++.h>
    
    using namespace std;
    
    vector<int> ve[110000], V[110000];
    long long ans[110000], Base, del[410000];
    int sum[110000], L[110000], R[110000], st[110000], Time, n, x, y;
    
    bool cmp(int x, int y) {
        return L[x] > L[y];
    }
    
    void dfs(int k, int f) {
        L[k] = ++Time;
        sum[k] = 1;
        for (int i = 0; i < (int) ve[k].size(); i++)
            if (ve[k][i] != f)
                dfs(ve[k][i], k), sum[k] += sum[ve[k][i]];
        R[k] = Time;
    }
    
    void modify(int k, int q, int h, int l, int r, int d) {
        if (l <= q && h <= r)
            del[k] += d;
        else {
            if (r <= (q + h) / 2)
                modify(k * 2, q, (q + h) / 2, l, r, d);
            else if ((q + h) / 2 < l)
                modify(k * 2 + 1, (q + h) / 2 + 1, h, l, r, d);
            else
                modify(k * 2, q, (q + h) / 2, l, r, d), modify(k * 2 + 1, (q + h) / 2 + 1, h, l, r, d);
        }
    }
    
    void dfs(int k, int q, int h, long long now) {
        now += del[k];
        if (q == h)
            ans[q] = now;
        else {
            dfs(k * 2, q, (q + h) / 2, now);
            dfs(k * 2 + 1, (q + h) / 2 + 1, h, now);
        }
    }
    
    void doit(vector <int> V) {
        if (V.size() == 0)
            return ;
        Base += n;
        sort(V.begin(), V.end(), cmp);
        int len = 0;
        for (int i = 0; i < (int) V.size(); i++) {
            vector <int> T;
            while (len && L[V[i]] <= L[st[len]] && L[st[len]] <= R[V[i]]) {
                T.push_back(st[len]);
                len--;
            }
            st[++len] = V[i];
            int r = T.size() - 1;
            for (int p = ((int) ve[V[i]].size()) - 1; p >= 0; p--)
                if (sum[ve[V[i]][p]] < sum[V[i]]) {
                    int q = ve[V[i]][p];
                    int kk = sum[q];
                    int RR = r;
                    while (RR >= 0 && L[q] <= L[T[RR]] && L[T[RR]] <= R[q])
                        RR -= 1;
                    for (int j = RR + 1; j <= r; j++)
                        kk -= sum[T[j]];
                    modify(1, 1, n, L[q], R[q], kk);
                    for (int j = RR + 1; j <= r; j++)
                        modify(1, 1, n, L[T[j]], R[T[j]], -kk);
                    r = RR;
                }
            
        }
        int kk = n;
        for (int j = 1; j <= len; j++)
            kk -= sum[st[j]];
        modify(1, 1, n, 1, n, kk);
        for (int j = 1; j <= len; j++)
            modify(1, 1, n, L[st[j]], R[st[j]], -kk);
    }
    
    int main() {
        scanf("%d", &n);
        for (int i = 1; i <= n; i++)
            scanf("%d", &x), V[x].push_back(i);
        for (int i = 1; i < n; i++) {
            scanf("%d%d", &x, &y);
            ve[x].push_back(y);
            ve[y].push_back(x);
        }
        dfs(1, 0);
        for (int i = 1; i <= 100000; i++) {
            doit(V[i]);
        }
        dfs(1, 1, n, 0);
        for (int i = 1 ; i <= n; i++)
            printf("%lld\n", Base - ans[L[i]]);
    }
    
  • + 0 comments

    here is hackerrank unique colors solution

  • + 1 comment

    Someone has hacked my account. Please help me!

No more comments