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  1. Prepare
  2. Data Structures
  3. Trees
  4. Tree: Huffman Decoding
  5. Discussions

Tree: Huffman Decoding

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537 Discussions

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  • wubrafiqcse807
     + 0 comments

    Simple Java Solutions :

    void decode(String s, Node root) {
        String str = "";
        Node head = root;
        for(int i = 0;i<s.length();i++) {
            if(s.charAt(i)=='0') {
                head = head.left;
            }
            if(s.charAt(i)=='1') {
                head = head.right;
            }
             str+=head.data;
            if(head.left==null && head.right==null) {

                head = root;
        }
    }
    System.out.println(str.replace("\0", ""));  
}

  • abdull_alkhatib
     + 1 comment

    This test is broken for java and I just earned points for printing what I am reading from stdin ....

  • vikitsonkata
     + 0 comments
    void decode_huff(node * root, string s) {
    node* curr = root;
    string print;
    while(!s.empty())
    {
        if(curr->data != '\0')
        {
            print += curr->data;
            curr = root;
            continue;
        }
        if(s.front() == '0')
        {
            curr = curr->left;
        }
        else
        {
            curr = curr->right;
        }
        s.erase(0, 1);
    }
    print += curr->data;
    cout << print;
}

  • ludovic_tirtiaux
     + 0 comments
    // C++ version
string ss;
int idx;
int len;

void CheckNode(node * root) {
    
    if (root->data > 0) {
        std::cout << root->data;
        return;
    }
        
    if (ss[idx++] == '0') {
        CheckNode(root->left);
    }
    else {
        CheckNode(root->right);
    }
    
}

void decode_huff(node * root, string s) {
    if (root == nullptr)
        return;
    
    ss = s;
    len = ss.length();
    idx = 0;
    
    
    while (idx < len) {
        CheckNode(root);     
    }
    std::cout << '\n';
}

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     + 0 comments

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