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Precalculating all values in range for the inverse of the function you're actually interested in feels like a weird solution until you realize said inverse grows exponentially . . . I think. Frankly I wasn't very rigorous in my argument to myself that it isn't superexponential.
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Tower Breakers - The Final Battle
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Precalculating all values in range for the inverse of the function you're actually interested in feels like a weird solution until you realize said inverse grows exponentially . . . I think. Frankly I wasn't very rigorous in my argument to myself that it isn't superexponential.