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  1. Prepare
  2. Algorithms
  3. Warmup
  4. Time Conversion
  5. Discussions

Time Conversion

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5155 Discussions

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  • julianwilliams21
     + 0 comments
    char* timeConversion(char* str) {
    int h,m,s;
    sscanf(str, "%d:%d:%d", &h, &m, &s);
    if (h == 12) h = 0;
    if (str[8] == 'P') h += 12;
    
    static char out[9];
    sprintf(out, "%02d:%02d:%02d", h, m, s);
    return out;
}

  • aayushg263
     + 0 comments

    Is this code good??

    def timeConversion(s):
    hour = int(s[:2])
    minute = s[3:5]
    second = s[6:8]
    am_pm = s[8:]

    if am_pm == "AM":
        if hour == 12:
            print(f"0{hour - 12}:{minute}:{second}")
        else:
            print(f"0{hour}:{minute}:{second}")

    elif am_pm == "PM":
        if hour == 12:
            print(f"{hour}:{minute}:{second}")
        else:
            print(f"{hour + 12}:{minute}:{second}")

  • pranikolli
     + 0 comments

    Any tips for coming up with simpler solutions? I keep coming up with complicated solutions. my solution to this problem was:

            String amOrPm = parts[parts.length - 2];
        if(amOrPm.equals("A")){
            if(parts[0].equals("1") && parts[1].equals("2")) return s.replaceFirst("12", "00").substring(0, parts.length - 2);
             else return s.substring(0, parts.length - 2);
            
        } else if(amOrPm.equals("P")) {
            if(parts[0].equals("1") && parts[1].equals("2")) return s.substring(0, parts.length - 2);
            else return s.replaceFirst((s.substring(0,2)), (Integer.parseInt(s.substring(0,2)) + 12) + "").substring(0, parts.length - 2);
        }
        
        return s;

  • bhupankarg2
     + 0 comments
    string timeConversion(string s)
{
    if(s[8] == 'A')
    {
        if(s[0] == '1' && s[1] == '2')
        {
            s[0] = '0';
            s[1] = '0';
        }
    }
    else if(s[8] == 'P')
    {
        if(s[0] != '1' || s[1] != '2')
        {
            s[0] = ((((((s[0] - '0') * 10) + (s[1] - '0')) + 12) / 10) + '0');
            s[1] = ((((((s[0] - '0') * 10) + (s[1] - '0')) + 12) % 10) + '0');
        }
    }
    s.erase(8, 2);
    return s;
}

  • aliraza4130633
     + 0 comments

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