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  1. Tree: Height of a Binary Tree
  2. Discussions

Tree: Height of a Binary Tree

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13 Discussions

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  • braunjory
     + 0 comments

    confirmed broken in JS.

  • perfetti_stefano
     + 0 comments

    How was this problem classified as requiring advanced problem solving? It is much easier than many supposedly easy problems in this preparation kit.

  • vadym_usatiuk
     + 0 comments

    Java 8, O(log n)

    public static int height(Node root) {
            if (root == null) {
                return -1;
            } else {
                return 1 + Math.max(height(root.left), height(root.right));
            }
        }

  • dariaabaklanova
     + 0 comments

    It seems it's broken on JS: it's comparing NaN with root.data preparing the Tree. and all the nodes are on the right then...

  • logan_r_smith0
     + 1 comment

    C++ using a stack and iteration instead of recursion.

        int height(Node* root) {
        struct Frame {
            Node* node{};
            int height = 0;
        };
        std::stack<Frame> stack;
        stack.push({root});
        int max = INT_MIN;
        while (!stack.empty()) {
            const auto top = stack.top();
            stack.pop();
            max = std::max(max, top.height);
            if (top.node->right)
                stack.push({top.node->right, top.height + 1});
            if (top.node->left)
                stack.push({top.node->left, top.height + 1});
        }
        return max;
    }

    • logan_r_smith0
       + 0 comments

      C++, recursion.

          int height(Node* root) {
        if (!root || (!root->left && !root->right))
            return 0;
        return 1 + std::max(
            height(root->left),
            height(root->right)
        );
    }

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