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  1. Smart Number 2
  2. Discussions

Smart Number 2

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35 Discussions

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  • shadowinc
     + 0 comments

    def is_smart_number(num):

    val = int(math.sqrt(num))
if **num == int(math.pow(val , 2))**:
    return True
return False

  • ravisharma_mu
     + 0 comments

    Only square numbers have odd factors.

  • vadym_usatiuk
     + 0 comments

    Java 7

            if (num == val * val)

  • leoa451
     + 0 comments

    C++ solution

    bool is_smart_number(int num) {
    int val = (int) sqrt(num);
    if(num==1 || (num>=4 && val>1 && num == val*val))
        return true;
    return false;
}

  • marcellodelgado1
     + 3 comments

    I'm having an issue where my output and the expected output are exactly identical, but the grader is saying I have the wrong answer.

    Has anyone else had this issue?