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  1. Sherlock and the Valid String
  2. Discussions

Sherlock and the Valid String

  • davidsonekpokpo1
     + 0 comments

    Python Solution using a dictionary:

    def isValid(s):
    # Write your code here
    stringDict={}
    
    for letter in s:
        stringDict[letter]= stringDict.get(letter,0) + 1 
    dictValues= list(stringDict.values())
    isRemovedOne=False
    for i in range(1,len(dictValues)):
        diff= abs(dictValues[i]- dictValues[i-1])
        if  diff == 0:
            continue
        else:
            if not isRemovedOne:
                isRemovedOne=True
                dictValues[i]-=1
            else:
                return "NO"
    return "YES"