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  1. Sherlock and Array
  2. Discussions

Sherlock and Array

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54 Discussions

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  • poolen108
     + 0 comments

    For arr s.t. arr == {1}, the left and right can't add up to zero. Even saying there is a "left" and a "right" is nonsensical. Null + Null != 0.

  • adebayovicktor
     + 0 comments
    def balancedSums(arr):
    # Write your code here
    total_sum = sum(arr)
    right_acc = 0
    for index in range(len(arr)):
        total_sum -= arr[index]
        if (right_acc == total_sum):
            return "YES"
        right_acc += arr[index]
    return "NO"

  • shadowinc
     + 0 comments

    def balancedSums(arr):

    left = 0
right = sum(arr)
for i in range(len(arr)):
    right -= arr[i]
    if left == right:
        return 'YES'
    left += arr[i]
return 'NO'

  • henrylong719
     + 0 comments

    TypeScript

    function balancedSums(arr: number[]): string {
  let totalSum = arr.reduce((acc, cur) => acc + cur);

  let leftSum = 0;

  for (let i = 0; i < arr.length; i++) {
    let rightSum = totalSum - leftSum - arr[i];

    if (rightSum === leftSum) return 'YES';

    leftSum += arr[i];
  }

  return 'NO';
}

  • douglas_pasqua
     + 0 comments

    php

    function balancedSums($arr) {
    $n = count($arr);
    $sum_total = array_sum($arr);
    $sum_left = 0;

    for($i = 0; $i < $n; $i++) {
        if($i == 0) {
            $sum_left = 0;
        } else {
            $sum_left += $arr[$i - 1];
        }

        $sum_right = $sum_total - $sum_left - $arr[$i];
        if($sum_left == $sum_right) {
            return 'YES';
        }
    }
    return 'NO';
}