We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Left Rotation
  2. Discussions

Left Rotation

Sort by

recency

|

154 Discussions

|

  • eypates04
     + 3 comments
    fun leftRotation(d: Int, arr: Array<Int>): Array<Int> {
    val result = arr.toMutableList()

    for (i in 0 until d) {
        val first  = result.first()
        result.removeAt(0)
        result.add(first)
    }

    return result.toTypedArray()
}

  • harrydunn333
     + 0 comments
    def rotateLeft(d, arr):
    for i in range(d):
        arr.append(arr.pop(0))
    return arr

  • chreachhunneng
     + 0 comments

    I think this solution only few line in java

        public static List<Integer> rotateLeft(int d, List<Integer> arr) {
        for(int i=0; i < d; i++){
            arr.add(arr.remove(0));
        }
        return arr;
    }

  • mohapatra_shrey1
     + 0 comments

    Python Solution with minimum no of rotations remainder = minimum no. of rotations or swaps required on the arr

    def rotateLeft(d, arr):
    n=len(arr)
    rem=d%n
    if d==0 or rem==0:
        return arr
    else:
        for i in range(rem):
            arr.append(float('-inf'))
            arr[0],arr[-1]=arr[-1],arr[0]
            arr.pop(0)
        return arr

  • vinayak25nair
     + 0 comments

    Java Easy solution

    public static List<Integer> rotateLeft(int d, List<Integer> arr) {

    if(d==arr.size()){
        return arr;
    }
    int i=0;
    for(;i<d;d--){
        int temp = arr.get(i);
        arr.remove(i);
        arr.add(temp);
    }
    return arr;
}