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  1. Prepare
  2. Algorithms
  3. Implementation
  4. The Time in Words
  5. Discussions

The Time in Words

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944 Discussions

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  • egraceq
     + 0 comments

    Bugging out in in TypeScript. The 1, 1 test fails when it should succed.

  • wifivop476
     + 0 comments

    The question setters missed out on an interesting test case i.e. with minutes=59 I used the conditional clause for minutes=1 only for the case minutes < 30 and it passed all the test cases. Felina Maldonado

  • michal_dwojak92
     + 0 comments

    C# solution:

    public static string timeInWords(int h, int m)
    {
        string outputPrint = string.Empty;
        Dictionary<int, string> numbersTime = new Dictionary<int, string>
        {
            { 0, "o' clock" }, { 1, "one" }, { 2, "two" }, { 3, "three"}, { 4, "four"},
            { 5, "five"}, { 6, "six"}, { 7, "seven"}, { 8, "eight"}, { 9, "nine"},
            {10, "ten"}, {11, "eleven"}, {12, "twelve"}, {13, "thirteen"}, {14, "fourteen"},
            {15, "quarter"}, {16, "sixteen"}, {17, "seventeen"}, {18, "eighteen"},
            {19, "nineteen"}, {20, "twenty"}, {21, "twenty one"}, {22, "twenty two"},
            {23, "twenty three"}, {24, "twenty four"}, {25, "twenty five"}, {26, "twenty six"},
            {27, "twenty seven"}, {28, "twenty eight"}, {29, "twenty nine"}, {30, "half"}
        };
        switch (m)
        {
            case 0:
                outputPrint = numbersTime[h] + " " + numbersTime[0];
                break;
            case 15:
                outputPrint = numbersTime[m] + " past " + numbersTime[h];
                break;
            case 30:
                outputPrint = numbersTime[m] + " past " + numbersTime[h];
                break;
            case 45:
                outputPrint = numbersTime[60 - m] + " to " + numbersTime[h + 1];
                break;
            case <=10:
                outputPrint = numbersTime[m] + " minute past " + numbersTime[h];
                break;
            case <= 30:
                outputPrint = numbersTime[m] + " minutes past "+ numbersTime[h];
                break;
            case >30:
                outputPrint = numbersTime[60 - m] + " minutes to " + numbersTime[h+1];
                break;
        }
        return outputPrint;
    }

  • voronin_ilia
     + 0 comments

    C++ Solution

    const map<int, string> nums{
    {1, "one"}, {2, "two"}, {3, "three"}, {4, "four"}, {5, "five"},
    {6, "six"}, {7, "seven"}, {8, "eight"}, {9, "nine"}, {10, "ten"},
    {11, "eleven"}, {12, "twelve"}, {13, "thirteen"}, {14, "fourteen"},
    {15, "quarter"}, {16, "sixteen"}, {17, "seventeen"}, {18, "eighteen"},
    {19, "nineteen"}, {20, "twenty"}, {21, "twenty one"}, {22, "twenty two"},
    {23, "twenty three"}, {24, "twenty four"}, {25, "twenty five"},
    {26, "twenty six"}, {27, "twenty seven"}, {28, "twenty eight"},
    {29, "twenty nine"}, {30, "thirty"}};
    
string timeInWords(int h, int m) {
  
  if (m == 0) {
    return nums.at(h) + " o' clock";
  } else
  if(m > 30) {
    m = 60 - m;
    
    return nums.at(m) + 
      (m != 15 ? ((m == 1 || m == 21) ? " minute" : " minutes") : "") +
      " to " + nums.at((h+1 < 12) ? h+1 : 1);
  } else 
  if (m == 30) {
    return "half past " + nums.at(h);
  } else {
    return nums.at(m) + 
      (m != 15 ? ((m == 1 || m == 21) ? " minute" : " minutes") : "") +
      " past " + nums.at(h);
  }
}

  • chhunklinton91
     + 0 comments
    def timeInWords(h, m):
    num_words = {
        1: "one", 2: "two", 3: "three", 4: "four", 5: "five", 6: "six",
        7: "seven", 8: "eight", 9: "nine", 10: "ten", 11: "eleven",
        12: "twelve", 13: "thirteen", 14: "fourteen", 15: "quarter",
        16: "sixteen", 17: "seventeen", 18: "eighteen", 19: "nineteen",
        20: "twenty", 21: "twenty one", 22: "twenty two", 23: "twenty three",
        24: "twenty four", 25: "twenty five", 26: "twenty six", 27: "twenty seven",
        28: "twenty eight", 29: "twenty nine", 30: "half"
    }
    
    if m == 0:
        return f"{num_words[h]} o' clock"
    
    if m == 15 or m == 30:
        return f"{num_words[m]} past {num_words[h]}"
    
    if m == 45:
        next_hour = h + 1 if h < 12 else 1
        return f"quarter to {num_words[next_hour]}"
    
    if m < 30:
        minute_word = "minute" if m == 1 else "minutes"
        return f"{num_words[m]} {minute_word} past {num_words[h]}"
    
    next_hour = h + 1 if h < 12 else 1
    minute_word = "minute" if (60 - m) == 1 else "minutes"
    return f"{num_words[60 - m]} {minute_word} to {num_words[next_hour]}"