def theLoveLetterMystery(s):
    return sum([abs(ord(s[i]) - ord(s[-(i + 1)])) for i in range(len(s) // 2)])

int theLoveLetterMystery(string s) {
    int ans = 0 , start = 0, end = s.size() - 1;
    while(start < end){
        ans += abs(s[start] - s[end]);
        start++; end--;
    }
    return ans;
}

function theLoveLetterMystery(s: string): number {
    let operations = 0

    // Calculate the sum of the differences between opposite pairs of characters (number ascii).
    for (let i = 0; i < Math.floor(s.length / 2); i++) {
        let reverse_i = s.length - i - 1
        if (s[i] != s[reverse_i]) {
            operations += Math.abs(s.charCodeAt(i) - s.charCodeAt(reverse_i))
        }
    }

    return operations
}

public static int theLoveLetterMystery(String s) {
    // Write your code here
    int count = 0;
        StringBuilder sb = new StringBuilder(s);
        String str = sb.reverse().toString();
        if (s.contentEquals(str)) {
            return count;
        } else {
            for (int i = 0; i < s.length() / 2; i++) {
                count += Math.abs(s.charAt(i) - s.charAt(s.length() - 1 - i));
            }
            return count;
        }
    }

int theLoveLetterMystery(string s) {
    int cnt = 0;
    int k = 0;
    int left_part = 0;
    int right_part = 0;
    while (k < int(s.size() / 2)) {
        left_part = int(s[k]);
        right_part = int(s[s.size() - k - 1]);
        while (left_part != right_part) {
            if (left_part < right_part) {
                cnt++;
                right_part -= 1;
            } else if (left_part > right_part) {
                cnt++;
                left_part -= 1;
            }
        }
        k++;
    }
    return cnt;
}