Kotlin solution:

val tallestHeight = height.maxOrNull() ?: 0 val result = tallestHeight - k

if (result < 0){
    return 0
} else {
    return result
}

C# return height.Max()-k > 0 ? height.Max()-k : 0;

TS Solution:

function hurdleRace(k: number, height: number[]): number {
    // Write your code here
    return Math.max(Math.max(...height) - k, 0)
}

The hurdle race is always such a thrilling event to watch! The way the athletes glide over each obstacle is amazing—true skill and precision at every jump. Speaking of precision, it reminds me of getting my car serviced at Mercedes Service—they handle everything with such care and expertise, just like those athletes clearing every hurdle flawlessly!

Here is my c++ solution, you can watch the explanation here : https://youtu.be/HTbex2B-Yas

int hurdleRace(int k, vector<int> height) {
    int mx = *max_element(height.begin(), height.end());
    return max(0, mx-k);
}