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- Probability & Statistics - Foundations
- The Central Limit Theorem #5
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The Central Limit Theorem #5
The Central Limit Theorem #5
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74+11(47-X)<20 X>51.91 Then apply P(X>51.91) on a normal distribution of N(50,10/sqrt(11)), and you'll get 0.2632
If we start with 74,000 gallons and need to have at least 20,000 gallons after 11 weeks, then we cannot afford to lose more than (74,000 - 20,000)/11 each week.
We also know that if we sell on average 50,000 gallons each week and add a constant 47,000 gallons each week, then on average we can expect to lose 3,000 gallons each week.
Now knowing that on average we will lose 3,000 gallons each week, what is the probability we will lose more than (74,000-20,000)/11 each week?
The distribution of the remaining supply is really not normal anymore and is only positive since you clearly cant have a negative balance. My approach is to explicitly simulate the weekly remainder but having a check for less than 0 remainder, in which case, I force it to take the weekly delivered amount as the left over amount for that week.
I'm stucked at the following challenge #6 because this one's implementation is wrong, as anything > 0.1999 will pass.
Can someone look at my implementation and tell me where I'm failing?
Below the calculations to support the choice of my equations (init_supply → supply, delivery → X, weeks → w)