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n = 100
s = 80
u = 500
sample_s = 80/10 = 8
e are given µ = 500, σ = 80, n = 100.
a. P(490 < x <¯ 510) = P((490−500)/(√80/100)< z < (490−500)/(√80/100)) = P(−1.25 < z < 1.25) = 0.8944 − (1 − 0.8944) = 0.7888.
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The Central Limit Theorem #3
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n = 100 s = 80 u = 500 sample_s = 80/10 = 8 e are given µ = 500, σ = 80, n = 100. a. P(490 < x <¯ 510) = P((490−500)/(√80/100)< z < (490−500)/(√80/100)) = P(−1.25 < z < 1.25) = 0.8944 − (1 − 0.8944) = 0.7888.