The "Subarray Division" problem typically involves finding the number of contiguous subarrays of a given array that sum up to a specific value. A common variation of this problem is where you are given an array of integers, a target sum, and a required subarray length. One effective approach to solving this problem is using CBT training in Milton Keynes the sliding window technique if the subarray length is fixed.

sliding window

The "Subarray Division" problem typically involves finding the number of contiguous subarrays of a given array that sum up to a specific value. A common variation of this problem is where you are given an array of integers, a target sum, and a required subarray length. One effective approach to solving this problem is using Snptube the sliding window technique if the subarray length is fixed.

python 3

def birthday(s, d, m): chococalate = 0 total = sum(s[:m])

if total == d:
    chococalate += 1

for i in range(len(s)-m):
    total = total - s[i] + s[i+m]

    if total == d:
        chococalate +=1

return chococalate

Here is my O(N) c++ solution, you can watch the explanation here : https://youtu.be/L2fkDuGrxiI

int birthday(vector<int> s, int d, int m) {
    if(s.size() < m) return 0;
    int su = accumulate(s.begin(), s.begin() + m, 0), result = 0;
    if(su == d) result++;
    for(int i = m; i < s.size(); i++){
        su += s[i];
        su -= s[i-m];
        if(su == d) result++;
    }
    return result;
 }