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  1. Prepare
  2. Python
  3. Strings
  4. Text Wrap
  5. Discussions

Text Wrap

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1896 Discussions

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  • saipranavk8
     + 0 comments

    def wrap(string, max_width): return textwrap.fill(string,max_width)

    this is enought for all the test cases

  • 17ishikajain
     + 0 comments

    without textwrap:- def wrap(string, max_width):

    inilen = 0

for i in range(len(string)):

    print(string[i],end ='')
    inilen+=1
    if inilen == max_width:
        inilen = 0
        print('\n',end='')

return ''

    if name == 'main':

  • Shamanand1y2
     + 0 comments
    import textwrap
def wrap(string, max_width): 
        return textwrap.fill(string,max_width)


string, max_width = input(), int(input())
result = wrap(string, max_width)
print(result)

  • h3538773699
     + 0 comments
    import textwrap

def wrap(string, max_width):
    
    str = textwrap.fill(text = string, width = max_width)
    
    return str

if __name__ == '__main__':
    string, max_width = input(), int(input())
    result = wrap(string, max_width)
    print(result)

  • ujjwalkarki_off1
     + 1 comment
    import textwrap

def wrap(string, max_width):
    wrapper = textwrap.TextWrapper(width=max_width)
    
    return '\n'.join(wrapper.wrap(text = string))

if __name__ == '__main__':
    string, max_width = input(), int(input())
    result = wrap(string, max_width)
    print(result)

    • f_p_khan27
       + 2 comments

      can you explain the return statemen of your code?

      • h3538773699
         + 0 comments

        I think it should return a string, for example, my_string = ''.join(my_list). This line of code means to concatenate all the elements in a list called my_list into a single string, and store the result in the my_string variable.

      • arkopdas
         + 0 comments

        It's joining the charcters with a '\n' or enter after wrapping the string and returns the joined characters.

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