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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Taum and B'day
  5. Discussions

Taum and B'day

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931 Discussions

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  • alban_tyrex
     + 0 comments

    Here is my simple c++ solution, you can watch the explanation here : https://youtu.be/T9sxEzAbp-M

    long taumBday(int b, int w, int bc, int wc, int z) {
    long bp = min(bc, wc + z);
    long wp = min(wc, bc + z);
    return bp * b + wp * w;
}

  • g_azabache1
     + 1 comment

    This is my code in C# 

        public static long taumBday(int b, int w, int bc, int wc, int z)
    {
        long normalCost = (long)b * bc + (long)w * wc;
        long alternativeCost1 = (long)b * bc + (long)w * (bc + z);
        long alternativeCost2 = (long)w * wc + (long)b * (wc + z);
        return Math.Min(normalCost, Math.Min(alternativeCost1, alternativeCost2));
    }

  • jmcparland
     + 0 comments

    Haskell:

    module Main where

import Control.Monad (replicateM_)

solve :: Int -> Int -> Int -> Int -> Int -> Int
solve b w bc wc z
    | bc > wc + z = (b + w) * wc + b * z
    | wc > bc + z = (b + w) * bc + w * z
    | otherwise = b * bc + w * wc

main :: IO ()
main = do
    cases <- readLn :: IO Int
    replicateM_ cases $ do
        [b, w] <- map read . words <$> getLine
        [bc, wc, z] <- map read . words <$> getLine
        print $ solve b w bc wc z

  • yossefibrahim7oo
     + 0 comments
    def taumBday(b, w, bc, wc, z):
    # Write your code here
    res= (w*wc) + (b*bc)
    should_convert = z < abs(bc-wc)
    if should_convert:
        if bc-wc > 0:
            bc = wc+z
            return (w*wc) + (b*bc)
        if wc-bc > 0:
            wc = bc+z
            return (w*wc) + (b*bc)  
    return res

  • vuhuutuan0
     + 1 comment

    This want me to return number but in typescript number have limit so there is noway to return it (or idk the way). Example must return 617318315833461267, the number reduce to 617318315833461200 make my answer wrong