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  1. Prepare
  2. Algorithms
  3. Bit Manipulation
  4. Sum vs XOR
  5. Discussions

Sum vs XOR

  • alban_tyrex
     + 0 comments

    Here is my C++ solution, you can watch the explanation here : https://youtu.be/yj0yNv6BZa8

    long sumXor(long n) {
    long result = 1;
    while(n) {
        result *= (n % 2) ? 1 : 2;
        n /= 2;
    }
    return result;
}