Sum of Digits of a Five Digit Number Discussions | C | HackerRank
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  2. C
  3. Conditionals and Loops
  4. Sum of Digits of a Five Digit Number
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Sum of Digits of a Five Digit Number

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734 Discussions

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  • prasannkumar2k91
     + 0 comments

    int s=0;

    while(n>0){

     s+=n%10;

    n/=10;        
}

printf("%d",s);

  • chetan142006
     + 0 comments

    include

    include

    include

    include

    int main() {

    int n;
scanf("%d", &n);
//Complete the code to calculate the sum of the five digits on n.
int sum=0;
while(n>0){
    int r=n%10;
    sum+=r;
    n=n/10;
}
printf("%d",sum);
return 0;

    }

  • meenakshimohan31
     + 0 comments
    #include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
    int n,i,sum=0;
    scanf("%d", &n);
    for(i=0;i<5;i++){
        sum+=n%10;
        n/=10;
    }
    printf("%d",sum);
    return 0;
}

  • moulidirisala
     + 0 comments

    \ while(n>0){ int a = n%10; sum=sum+a; n=n/10; } use while loop

  • su_fraga5
     + 0 comments

    int main() {

    int n;
scanf("%d", &n);
//Complete the code to calculate the sum of the five digits on n.
int sum = 0;

for (int i = 1; i < 6; i++ ){
    sum += (n%((int)pow(10,i)))/(pow(10, i-1));
    n -= n%(int)pow(10, i);
}

printf("%i", sum);

return 0;

    }