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Sum of Digits of a Five Digit Number

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  • + 0 comments

    include

    int main() {

    int n;
    scanf("%d", &n);
    int sum=0;
    while(n>0)
    {
        sum+=n%10;
        n=n/10;
    }
    printf("%d",sum);
    return 0;
    

    }

  • + 0 comments
    #include <stdio.h>
    #include <string.h>
    #include <math.h>
    #include <stdlib.h>
    
    int main() {
    	
        int n,res,a=1;
        int sum=0;
        scanf("%d", &n);
        //Complete the code to calculate the sum of the five digits on n.
        int remaining=n;
        res= n%10;
        sum=sum+res;
        while(a<=4){
            remaining=remaining/10;
                   
            res=remaining%10;
    
            sum=sum+res;
    
            a++;
        }
        printf("%d",sum);
        return 0;
    }
    
  • + 0 comments

    include

    include

    include

    include

    int main() {

    int n;
    scanf("%d", &n);
    //Complete the code to calculate the sum of the five digits on n.
    if (n < 10000 || n > 99999) {
        printf("Please enter a five-digit number.\n");
        return 1; 
    }
    
    int sum = 0; 
    for (int i = 0; i < 5; i++) {
        sum += n % 10; 
        n = n / 10;    
    }
    
    printf("%d\n", sum); 
    return 0;
    

    }

  • + 0 comments

    int main() {

    int n;
    int sum;
    scanf("%d", &n);
    
    for (int i=0; i<5; i++){
        sum += n % 10;
        n = n / 10;
    }
    printf("%d", sum);
    
    return 0;
    

    }

  • + 0 comments

    include

    include

    include

    include

    int main() {

    int n, sum=0;
    scanf("%d", &n);
    //Complete the code to calculate the sum of the five digits on n.
    sum = n/10000%10 + n/1000%10 + n/100%10 + n/10%10 + n/1%10;
    printf("%d", sum);
    return 0;
    

    }