Sum of Digits of a Five Digit Number Discussions | C | HackerRank

Sum of Digits of a Five Digit Number

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  • + 0 comments

    int main() {

    int n;
    int sum;
    scanf("%d", &n);
    
    for (int i=0; i<5; i++){
        sum += n % 10;
        n = n / 10;
    }
    printf("%d", sum);
    
    return 0;
    

    }

  • + 0 comments

    include

    include

    include

    include

    int main() {

    int n, sum=0;
    scanf("%d", &n);
    //Complete the code to calculate the sum of the five digits on n.
    sum = n/10000%10 + n/1000%10 + n/100%10 + n/10%10 + n/1%10;
    printf("%d", sum);
    return 0;
    

    }

  • + 0 comments

    int s=0;

    while(n>0){
    
         s+=n%10;
    
        n/=10;        
    }
    
    printf("%d",s);
    
  • + 0 comments

    include

    include

    include

    include

    int main() {

    int n;
    scanf("%d", &n);
    //Complete the code to calculate the sum of the five digits on n.
    int sum=0;
    while(n>0){
        int r=n%10;
        sum+=r;
        n=n/10;
    }
    printf("%d",sum);
    return 0;
    

    }

  • + 0 comments
    #include <string.h>
    #include <math.h>
    #include <stdlib.h>
    
    int main() {
        int n,i,sum=0;
        scanf("%d", &n);
        for(i=0;i<5;i++){
            sum+=n%10;
            n/=10;
        }
        printf("%d",sum);
        return 0;
    }