A subsequence of a sequence is a sequence which is obtained by deleting zero or more elements from the sequence.
You are given a sequence A
in which every element is a pair of integers i.e A
= [(a1, w1), (a2, w2),..., (aN, wN)].
For a subseqence B
= [(b1, v1), (b2, v2), ...., (bM, vM)] of the given sequence :
- We call it increasing if for every i (1 <= i < M ) , bi < bi+1.
- Weight(B) = v1 + v2 + ... + vM.
Task:
Given a sequence, output the maximum weight formed by an increasing subsequence.
Input:
The first line of input contains a single integer T. T test-cases follow. The first line of each test-case contains an integer N. The next line contains a1, a2 ,... , aN separated by a single space. The next line contains w1, w2, ..., wN separated by a single space.
Output:
For each test-case output a single integer: The maximum weight of increasing subsequences of the given sequence.
Constraints:
1 <= T <= 5
1 <= N <= 150000
1 <= ai <= 109, where i ∈ [1..N]
1 <= wi <= 109, where i ∈ [1..N]
Sample Input:
2
4
1 2 3 4
10 20 30 40
8
1 2 3 4 1 2 3 4
10 20 30 40 15 15 15 50
Sample Output:
100
110
Explanation:
In the first sequence, the maximum size increasing subsequence is 4, and there's only one of them. We choose B = [(1, 10), (2, 20), (3, 30), (4, 40)]
, and we have Weight(B) = 100
.
In the second sequence, the maximum size increasing subsequence is still 4, but there are now 5 possible subsequences:
1 2 3 4
10 20 30 40
1 2 3 4
10 20 30 50
1 2 3 4
10 20 15 50
1 2 3 4
10 15 15 50
1 2 3 4
15 15 15 50
Of those, the one with the greatest weight is B = [(1, 10), (2, 20), (3, 30), (4, 50)]
, with Weight(B) = 110
.
Please note that this is not the maximum weight generated from picking the highest value element of each index. That value, 115, comes from [(1, 15), (2, 20), (3, 30), (4, 50)], which is not a valid subsequence because it cannot be created by only deleting elements in the original sequence.