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  1. Prepare
  2. Algorithms
  3. Strings
  4. Strong Password
  5. Discussions

Strong Password

  • sayre_precure
     + 5 comments

    Got one pretty similar :)

    count = 0
cases = [r'[a-z]', r'[A-Z]', r'[\d]', r'[!@#$%^&*()\-+]']
for case in cases:
    if not re.search(case, password):
        count += 1

return max(count, 6 - n)