function minimumNumber(n: number, password: string): number {
    /**
     * simple
     * 1. check [password] missing [x] in length
     * 2. check [password] missing [y] in types of character
     * 3. return the larger [x] or [y]
     * 
     * why? 
     * if you miss 3 length but miss 1 type, you can write that missing type
     * in 3 character missing length to satisfy both conditions. 
     * if tou miss 1 length but miss 3 type, you need to type at least 3 character
     * in 3 type and that satisfy missing length condition too.
     */
    const check_miss_length = (): number => {
        if (n < 6) return 6 - n
        return 0
    }
    const check_miss_types = (): number => {
        const type_digit = (/([\d])/.test(password)) ? 0 : 1
        const type_lower = (/([a-z])/.test(password)) ? 0 : 1
        const type_upper = (/([A-Z])/.test(password)) ? 0 : 1
        const type_speci = (/([^a-z0-9A-Z])/.test(password)) ? 0 : 1
        return type_digit + type_lower + type_upper + type_speci;
    }

    return Math.max(check_miss_length(), check_miss_types())
}