include

using namespace std; int test(string s) { map mp; int sum = 0; for(int i = 0; i < s.length(); i++) { mp[s[i]]++; } for(auto it : mp) { if(it.second = 1) { sum += 1; } else if(it.second >= 2) { sum += 2; } } return sum; } int main() { int t; cin >> t; while(t--) { string s; cin >> s; cout << test(s) << endl; } return 0; }

C++ One Liner

int stringConstruction(string s) {
    return set<char>(s.begin(), s.end()).size();
}

The solution here is to count the number of unique occurrences of the characters, here is the explanation : https://youtu.be/UqqNcIUnsv8

solution 1 : using map

int stringConstruction(string s) {
    map<char, int> mp;
    int r = 0;
    for(int i = 0; i < s.size(); i++) if(!mp[s[i]]){
        mp[s[i]] = 1; r++;
    }
    return r;
}

solution 2 : using set

int stringConstruction(string s) {
    set<char> se(s.begin(), s.end());
    return se.size();
}

Python3

def stringConstruction(s):

return sum([1 for _ in set(s)])

Java

public static int stringConstruction(String s) {
        Set<Character> uniqueElements = new HashSet<>();
        for (char character : s.toCharArray()) {
            uniqueElements.add(character);
        }
        return uniqueElements.size();
    }