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Here is my c++ solution, you can watch video explanation here : https://youtu.be/Qs9rxqfzTs8
bool is_smart_number(int num) { int val = (int) sqrt(num); if(val * val == num) return true; return false; }
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Smart Number
You are viewing a single comment's thread. Return to all comments →
Here is my c++ solution, you can watch video explanation here : https://youtu.be/Qs9rxqfzTs8