You are viewing a single comment's thread. Return to all comments →
Why this problem doesnt support JavaScript language
function isSmartNumber(num) { var val = Math.floor(Math.sqrt(num)); if (val * val === num) { return true; } return false; }
Seems like cookies are disabled on this browser, please enable them to open this website
Smart Number
You are viewing a single comment's thread. Return to all comments →
Why this problem doesnt support JavaScript language