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  1. Prepare
  2. Algorithms
  3. Strings
  4. Sherlock and the Valid String
  5. Discussions

Sherlock and the Valid String

  • patrickgao2020
     + 0 comments

    I thought this one would be super easy but got humbled after I couldn't solve it in 15 minutes. Here is my Python solution!

    def isValid(s):
    s = Counter(s)
    frequencies = s.values()
    common = Counter(frequencies).most_common(1)[0][0]
    removed = False
    for frequency in frequencies:
        if abs(frequency - common) == 1 or (frequency != common and frequency == 1):
            if removed:
                return "NO"
            else:
                removed = True
        elif abs(frequency - common) > 1:
            return "NO"
    return "YES"