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  1. Prepare
  2. Algorithms
  3. Strings
  4. Sherlock and the Valid String
  5. Discussions

Sherlock and the Valid String

  • biren_yadav114
     + 0 comments

    python -

    def isValid(s):

    # Write your code here
s_dict = {}
count=0
for i in s:
    if i in s_dict:
        s_dict[i]+=1
    else:
        s_dict[i]=1
dict_val_list = list(s_dict.values())

for i in range(1,len(s_dict)):
    if dict_val_list[0] == dict_val_list[i]:
        continue          
    else:
        if count==0:
            count+=1
        else:
            return 'NO'
return 'YES'