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  1. Prepare
  2. Algorithms
  3. Strings
  4. Sherlock and the Valid String
  5. Discussions

Sherlock and the Valid String

  • priyanshugevra
     + 0 comments
     public static String isValid(String s) {
        Map<Character,Integer> map = new HashMap<>();
        int n = s.length();
        for(int i=0 ; i<n ; i++){
            map.put(s.charAt(i), map.getOrDefault(s.charAt(i), 0)+1);
        } 
        Map<Integer,Integer> freqMap = new HashMap<>();
        for(int fq : map.values())
        {
            freqMap.put(fq, freqMap.getOrDefault(fq, 0)+1);
        }
          if (freqMap.size() == 1) {
            return "YES"; 
        }
          if (freqMap.size() == 2) {
            for(int i : freqMap.values()){
                if(i==1) return "YES";
            }
        }

                can any one explain why it is paasing only 18/20 test cases? also please give the failed test case.

            `        
    return "NO";

}