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  1. Prepare
  2. Algorithms
  3. Strings
  4. Sherlock and the Valid String
  5. Discussions

Sherlock and the Valid String

  • alex_k5
     + 0 comments
    def isValid(s):
    cnt = Counter(Counter(s).values())
    val = list(cnt.keys())
    if len(cnt) == 1 or (len(cnt) == 2 and ((abs(val[0] - val[1]) == 1 and 1 in cnt.values()) or cnt[1]==1)):
        return 'YES'
    return 'NO'