Case 6 was 'failing' because of a print statement used for debugging... Success after removing print statement (which should have no effect on result)

My JavaScript Solution function squares(a, b) { const start = Math.ceil(Math.sqrt(a)); const end = Math.floor(Math.sqrt(b));
return end - start + 1 > 0 ? end - start + 1 : 0; }

c++

int squares(int a, int b) {
    int start = ceil(sqrt(static_cast<double>(a)));
    int end = floor(sqrt(static_cast<double>(b)));
    
    if (end < start) return 0;
    
    return end - start + 1;
}

Javascript simple solution: function squares(a, b) { const lower = Math.ceil(Math.sqrt(a)) const upper = Math.floor(Math.sqrt(b)) return upper-lower+1

}

Java solution :

public static int squares(int a, int b) {
    int startVal = (int)Math.sqrt(a);
    int endVal = (int)Math.sqrt(b);
    int sqrtcount = 0;

    for(int i=startVal ; i<=endVal ; i++) {
        int square = i*i;
        if(square>=a && square<=b) {
            sqrtcount++;
        }
    }

    return sqrtcount;
}