string balancedSums(vector<int> arr) {
    int ls = 0, rs = accumulate(arr.begin(), arr.end(), 0);
    for(int i = 0; i < arr.size(); i++){
        rs -= arr[i];
        if(i != 0) ls += arr[i-1];
        if(ls == rs) return "YES";
    }
    return "NO";
}

#!/bin/python3

import math
import os
import random
import re
import sys

# 
#Complete the 'balancedSums' function below.
#
# The function is expected to return a STRING.
# The function accepts INTEGER_ARRAY arr as parameter.
#
for t in range(int(input())):
    n = int(input())
    a = [int(b) for b in input().split()]
    s = sum(a)
    count = 0
    for i in range(n):
        if 2*count == s-a[i]:
            print("YES")
            break
        count += a[i]
    else:
        print("NO")

public static string balancedSums(List<int> arr)
{
    var len = arr.Count;
    var total = arr.Sum(x => (long)x);
    long leftSum = 0;
    long rightSum = total;

    for (int i = 0; i < len; ++i)
    {
        rightSum = rightSum - arr[i];
        var leftIndex = (i == 0) ? 0 : i - 1;

        if (i > 0)
        {
            leftSum = leftSum + arr[leftIndex];
        }

        if (leftSum == rightSum)
        {
            return "YES";
        }
    }

    return "NO";
}

def balancedSums(arr):
    # Write your code here
    left = 0
    right = sum(arr)
    for i in range(len(arr)):
        if i != 0:
            left += arr[i-1]
        right -= arr[i]
        if left == right:
            return 'YES'
    return 'NO'

def balancedSums(arr):
    # Write your code here
    lsum=0
    rsum=sum(arr)
    res='NO'
    for i in range(len(arr)):
        rsum-=arr[i]
        if lsum==rsum:
            res = 'YES'
            break
        lsum+=arr[i]
    return res