We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Security
  3. Functions
  4. Security Bijective Functions
  5. Discussions

Security Bijective Functions

  • Stealth_py
     + 0 comments

    My solution in Python 3:

    t=int(input())
s=list(map(int,input().split()))
if len(set(s)) == t:
    print("YES")
else:
    print("NO")