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  2. Mathematics
  3. Number Theory
  4. Scalar Products
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Scalar Products

  • TChalla
     + 1 comment

    Python3 solution

    # Enter your code here. Read input from STDIN. Print output to STDOUT
c, m, n = map(int,input().split())
if n == 1:
    print("0")
else:
    arr = [0 for i in range(2 * n + 2)]
    arr[0] = 0
    arr[1] = c
    l = []
    for i in range(2, 2 * n + 2):
        arr[i] = (arr[i - 1] + arr[i - 2]) % m
    for i in range(2, 2 * n - 2, 2):
        temp = (arr[i] * arr[i + 2] + arr[i + 1] * arr[i + 3]) % m
        l.append(temp)
        temp=(arr[i] * arr[i + 4] + arr[i + 1] * arr[i + 5]) % m
        l.append(temp)
    temp = (arr[2 * n - 2] * arr[2 * n] + arr[2 * n - 1] * arr[2 * n + 1]) % m
    l.append(temp)
    l = set(l)
    print(len(l))