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  • + 0 comments

    perl:

    while(<>){
        print if(/^[Hh][Ii]\s[^Dd]/)
    }
    
  • + 0 comments

    Java 15

    import java.io.*;
    import java.util.*;
    import java.util.regex.Pattern;
    import java.util.regex.Matcher;
    public class Solution {
        public static void main(String[] args) {
            Scanner scanner = new Scanner(System.in);
            int n = Integer.parseInt(scanner.nextLine());
            Pattern pattern = Pattern.compile("^[Hh][Ii]\\s[^dD]");
            for(int i=0;i<n;i++)
            {   String str = scanner.nextLine();
                Matcher matcher = pattern.matcher(str);
                if (matcher.find()) System.out.println(str);
            }
        }
    }
    
  • + 0 comments

    java solution

    import java.io.*;
    import java.util.*;
    import java.util.regex.Pattern;
    import java.util.regex.Matcher;
    
    public class Solution {
    
        public static void main(String[] args) {
            Scanner scanner = new Scanner(System.in);
            Pattern pattern = Pattern.compile("^hi (?!d).*", Pattern.CASE_INSENSITIVE);
            int n = Integer.parseInt(scanner.nextLine());
            for (int i = 0; i < n; i++) {
                Matcher matcher = pattern.matcher(scanner.nextLine());
                if (matcher.matches()) System.out.println(matcher.group(0));
            }
        }
    }
    
  • + 0 comments

    readable version:

    import re
    
    regex = re.compile(r'^[Hh][Ii] [^Dd]')
    
    n = int(input())
    for _ in range(n):
        line = input()
        if (regex.match(line)):
            print(line)
    
  • + 0 comments
    import re
    for _ in range(int(input())):
        if r := re.match(r"[Hh][Ii]\s[^Dd].+", input()):
            print(r.string)