double maxLimit = 9800;
int n = 49;

double mean = 205;
double stdDev = 15;

double meanX = n * mean;
double stdDevX = Math.sqrt(n) * stdDev;

double p = probability(meanX, stdDevX, maxLimit);

Explanation

If you need to calculate whether the sum of random values fit the limit then you need:

• multiply the mean in number of random values;
• multiply standard deviation in the square root of number of random values;
• the probability is calculated in the same way as in the previous problem.