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In a 52 card deck there are: - 4 suits - 13 cards per suit.
We want to find: P(2 cards of same suit wo/ replacement)
Favorable outcomes: 13C2 = 13!/2!(13-2)!
Total possibilities: 52C2 = 52!/2!(52-2)!
Since there are 4 suits: P(X) = 4 * 13C2/52C2
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Day 3: Cards of the Same Suit
You are viewing a single comment's thread. Return to all comments →
In a 52 card deck there are: - 4 suits - 13 cards per suit.
We want to find: P(2 cards of same suit wo/ replacement)
Favorable outcomes: 13C2 = 13!/2!(13-2)!
Total possibilities: 52C2 = 52!/2!(52-2)!
Since there are 4 suits: P(X) = 4 * 13C2/52C2