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  1. Prepare
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  3. 10 Days of Statistics
  4. Day 2: Compound Event Probability
  5. Discussions

Day 2: Compound Event Probability

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  • mickf4137
     + 0 comments

    Tackling complex problems, like some of the ones on HackerRank, can be super rewarding but also a bit overwhelming at times, especially when every detail has to be spot-on. I had a similar experience when I worked on organizing a large event with tons of moving parts—it needed flawless execution from start to finish. I ended up working with event companies in Miami and their attention to every tiny detail was impressive. It kind of reminded me of debugging a tricky code problem; they made sure everything was aligned perfectly, which made the whole event a success. Having experts like that can really save time and bring peace of mind, no matter the challenge!

  • Sarajayg19
     + 0 comments
    # Probabilities
urn_x = {'R': 4/7, 'B': 3/7}
urn_y = {'R': 5/9, 'B': 4/9}
urn_z = {'R': 1/2, 'B': 1/2}

# Scenarios
scenarios = [
    ['R', 'B', 'R'],  # R from X, B from Y, R from Z
    ['B', 'R', 'R'],  # B from X, R from Y, R from Z
    ['R', 'R', 'B']   # R from X, R from Y, B from Z
]

# Calculate probabilities for each scenario
total_probability = 0
for scenario in scenarios:
    probability = 1
    for i in range(3):
        if i == 0:
            probability *= urn_x[scenario[i]]
        elif i == 1:
            probability *= urn_y[scenario[i]]
        else:
            probability *= urn_z[scenario[i]]
    total_probability += probability
		
print("The probability of drawing 2 red balls and 1 black ball is:", total_probability)

  • n4m774r_d
     + 0 comments
    from fractions import Fraction
from math import prod
def probabilities(x, y, z):
    r1,r2 = Fraction(x[0], sum(x)),Fraction(y[0], sum(y))
    b1,b2 = Fraction(x[1], sum(x)),Fraction(y[1], sum(y))
    r3,b3 = Fraction(z[0], sum(z)),Fraction(z[1], sum(z))
    return [(r1,r2,b3),(r1,b2,r3),(b1,r2,r3)]

def calc_prob(x, y, z):
    to_mult = probabilities(x, y, z)
    prob = Fraction(0,1)
    for m in to_mult:prob += prod(m)
    return prob

x,y,z= (4, 3),(5, 4),(4, 4)

probability = calc_prob(x, y, z)
print(f"{probability.numerator}/{probability.denominator}")

  • Babak_D
     + 1 comment
    from itertools import product 
from fractions import Fraction

P = list(product([1]*4+[0]*3, [1]*5+[0]*4, [1]*4+[0]*4))

N = sum(1 for x in P if sum(x)==2)

print(Fraction(N, len(P)))

  • dostiyari0786
     + 0 comments

    Can you count probability of success in wedding photography aukland? I need fail and success both probability but it's not valid.