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  1. Prepare
  2. Tutorials
  3. 10 Days of Statistics
  4. Day 2: More Dice
  5. Discussions

Day 2: More Dice

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recency

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68 Discussions

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  • omowumimuse
     + 0 comments

    Great Question

  • pulkit_ag13
     + 0 comments

    can anyone tell me where we need to write the code i am only getting an option to tick the correct answer from MCQ.

  • adityakalyanbscc
     + 0 comments

    There are 6 possibilities on each die. On 2 dice, there are 6 * 6 = 36 possibilities

    There are 4 cases that match the desired criteria: (1,5) (5,1) (2,4) (4,2)

    This gives us a probability of 4/36 = 1/9

  • ejoaquinaguado
     + 0 comments

    a = [{a, b} for a in range(1, 7) for b in range(1, 7) if sum({a, b}) == 6] b = [{a, b} for a in range(1, 7) for b in range(1, 7)] print(len(a)/len(b) * 30/36)

    lol

  • rizvey_ma
     + 0 comments
    dice_1 = [1, 2, 3, 4, 5, 6]
dice_2 = dice_1.copy()

diff_and_sum_to_6 = 0
all_outcomes = 0
for v1 in dice_1:
    for v2 in dice_2:
        all_outcomes += 1
        if (v1 != v2) and (v1 + v2 == 6):
            diff_and_sum_to_6 += 1

prob_diff_and_sum_to_6 = diff_and_sum_to_6 / all_outcomes
print(prob_diff_and_sum_to_6)