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Day 2: Basic Probability
Day 2: Basic Probability
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check all possible pairs (total 36 pairs) in that only (4,6),(5,5),(5,6),(6,4),(6,5),(6,6) will not satisfiy atmost 9 (6 pairs) so 36-6=30 prob=30/36=5/6
ans=5/6
check all possible pairs (total 36 pairs) in that only (4,6),(5,5),(5,6),(6,4),(6,5),(6,6) will not satisfiy atmost 9 (6 pairs) so 36-6=30 prob=30/36=5/6
ans=
5/6
I kept getting it wrong because I kept forgetting to add the 9s. I was adding only the numbers less than 9
Failled 3 times without knowing i wouldnt have another try ..ever . Maybe it would be better to warn users about it .. OR after 3 errors , reset the challenge with another question and other parameters .. Or even better just forget about the multiple choice.. And let us code .
The given answer choices don't match the real answer; should be 1/9
There are total
36
outcomes (6 * 6
).Out of
36
, following outcomes are having sum greater than9
. So we don't count them:{4, 6}, {5, 5}, {5, 6}, {6, 4}, {6, 5}, {6, 6}
.So we are left with
36 - 6 = 30
. (outcomes having sum AT MOST 9)The answer is:
30/36 = 5/6
.