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  1. Prepare
  2. Tutorials
  3. 10 Days of Statistics
  4. Day 2: Basic Probability
  5. Discussions

Day 2: Basic Probability

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83 Discussions

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  • n4m774r_d
     + 0 comments

    Failled 3 times without knowing i wouldnt have another try ..ever . Maybe it would be better to warn users about it .. OR after 3 errors , reset the challenge with another question and other parameters .. Or even better just forget about the multiple choice.. And let us code .

  • waidyanatha1
     + 1 comment

    The given answer choices don't match the real answer; should be 1/9

  • rizvey_ma
     + 0 comments
    # Dice # 1
dice_1 = [1, 2, 3, 4, 5, 6]

# Dice # 2
dice_2 = dice_1.copy()

less_than_10 = 0
all_outcomes = 0

# Iterate through
for v1 in dice_1:
    for v2 in dice_2:
# add 1 for every pair to all_outcomes
        all_outcomes += 1
        if v1 + v2 < 10:
# add 1 for pairs that summed up to 9 or below to less_than_10.
            less_than_10 += 1

prob_less_than_10 = less_than_10 / all_outcomes
print(prob_less_than_10)

  • aiub_ali
     + 0 comments

    from itertools import product from fractions import Fraction

    P = list(product([1, 2, 3, 4, 5, 6], repeat=2))

    N = sum(1 for x in P if sum(x) <= 9)

    print(Fraction(N, len(P)))

  • smpsumedh13
     + 1 comment
    lst1=[1,2,3,4,5,6]
lst2=[1,2,3,4,5,6]
count=0
count_of_occurences=0
for i in range(0,len(lst1)):
    for j in range(0,len(lst2)):
        if lst1[i]+lst2[j]>0:
            count_of_occurences+=1
        if lst1[i]+lst2[j]<=9:
            count+=1

print(count)
print(count_of_occurences)