We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Tutorials
  3. 10 Days of Statistics
  4. Day 1: Interquartile Range
  5. Discussions

Day 1: Interquartile Range

Sort by

recency

|

421 Discussions

|

  • n4m774r_d
     + 0 comments
    S = sorted([v for v,f in zip(values,freqs) for _ in range(f)])
L = len(S)
Q1 = (S[(L//4)-1] + S[(L//4)]) /2 if L%4 == 0 else S[L//4]
Q3 = (S[3*(L//4)-1] + S[3*(L//4)]) /2 if 3*L%4 == 0 else S[3*L//4]
print( f"{Q3 - Q1:.1f}")

  • hamsasr02
     + 0 comments
    def interQuartile(values, freqs):
    # Print your answer to 1 decimal place within this function
    arr=[]
    for i in range(len(values)):
        ans = [values[i]] * freqs[i]  
        arr.extend(ans)  
    arr.sort()
    
    n = len(arr)
    mid = n//2
    
    if n%2 == 0:
        L = arr[:mid]
        U = arr[mid:]
    else:
        L = arr[:mid]
        U = arr[mid+1:]
    
    Q1 = median(L)
    Q3 = median(U)
    
    answer = Q3-Q1
    print(f"{answer:.1f}")
    
def median(a):
    n = len(a)
    mid = n//2
    if n % 2 == 0:
        median = (a[mid] + a[~mid]) / 2
    else:
        median = a[mid]
        
    return round(median)

  • rr6774727
     + 0 comments

    def interQuartile(values, freqs): # Create the data set S S = [] for i in range(len(values)): S += [values[i]] * freqs[i]

    S = sorted(S)
n = len(S)

def median(sub_arr):
    sub_n = len(sub_arr)
    mid = sub_n // 2
    if sub_n % 2 == 0:
        return (sub_arr[mid - 1] + sub_arr[mid]) / 2.0
    else:
        return sub_arr[mid]

# Calculate Q1
lower_half = S[:n // 2]
Q1 = median(lower_half)

# Calculate Q3
if n % 2 == 0:
    upper_half = S[n // 2:]
else:
    upper_half = S[(n // 2) + 1:]
Q3 = median(upper_half)

# Print the interquartile range to 1 decimal place
print(f"{Q3 - Q1:.1f}")

    if name == 'main': n = int(input().strip()) values = list(map(int, input().rstrip().split())) freqs = list(map(int, input().rstrip().split()))

    # Ensure that the number of elements in S is equal to the sum of freqs
assert len(values) == len(freqs), "The length of values and freqs must be the same"
assert sum(freqs) <= 1000, "The sum of frequencies must be less than or equal to 1000"

interQuartile(values, freqs)

  • 21KN1A04C5
     + 0 comments

    python 3

    def interQuartile(values, freqs):
    l=[]
    for i in range(len(values)):
        for j in range(freqs[i]):
            l.append(values[i])
    l=sorted(l)
    if len(l)%2==0:
        print(float(statistics.median(l[len(l)//2:])-statistics.median(l[:len(l)//2])))
    else:
        print(float(statistics.median(l[(len(l)//2)+1:])-statistics.median(l[:len(l)//2])))

  • cjkang0601
     + 0 comments

    I can't pass test 5 and 6 can somebody help me plz

    def interQuartile(values, freqs):
    # Print your answer to 1 decimal place within this function
    new_lst = []
    for i in range(n):
        temp_freq = freqs[i]
        for j in range(temp_freq-1):
            val.append(val[i])
    new_lst = sorted(val)
    #print(new_lst)
    med = statistics.median(new_lst)
    print(med)
    Q1 =[]
    Q3 =[]
    for i in range(len(new_lst)):
        if new_lst[i] < med:
            Q1.append(new_lst[i])
        elif new_lst[i] > med:
            Q3.append(new_lst[i])
    Q1_med = statistics.median(Q1)
    Q3_med = statistics.median(Q3)
    print(Q1_med, Q3_med)
    return round(Q3_med - Q1_med, 1)