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  1. Prepare
  2. Tutorials
  3. 10 Days of Statistics
  4. Day 1: Interquartile Range
  5. Discussions

Day 1: Interquartile Range

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421 Discussions

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  • n4m774r_d
     + 0 comments
    S = sorted([v for v,f in zip(values,freqs) for _ in range(f)])
L = len(S)
Q1 = (S[(L//4)-1] + S[(L//4)]) /2 if L%4 == 0 else S[L//4]
Q3 = (S[3*(L//4)-1] + S[3*(L//4)]) /2 if 3*L%4 == 0 else S[3*L//4]
print( f"{Q3 - Q1:.1f}")

  • [deleted]     + 0 comments
    def interQuartile(values, freqs):
    # Print your answer to 1 decimal place within this function
    arr=[]
    for i in range(len(values)):
        ans = [values[i]] * freqs[i]  
        arr.extend(ans)  
    arr.sort()
    
    n = len(arr)
    mid = n//2
    
    if n%2 == 0:
        L = arr[:mid]
        U = arr[mid:]
    else:
        L = arr[:mid]
        U = arr[mid+1:]
    
    Q1 = median(L)
    Q3 = median(U)
    
    answer = Q3-Q1
    print(f"{answer:.1f}")
    
def median(a):
    n = len(a)
    mid = n//2
    if n % 2 == 0:
        median = (a[mid] + a[~mid]) / 2
    else:
        median = a[mid]
        
    return round(median)

  • rr6774727
     + 0 comments

    def interQuartile(values, freqs): # Create the data set S S = [] for i in range(len(values)): S += [values[i]] * freqs[i]

    S = sorted(S)
n = len(S)

def median(sub_arr):
    sub_n = len(sub_arr)
    mid = sub_n // 2
    if sub_n % 2 == 0:
        return (sub_arr[mid - 1] + sub_arr[mid]) / 2.0
    else:
        return sub_arr[mid]

# Calculate Q1
lower_half = S[:n // 2]
Q1 = median(lower_half)

# Calculate Q3
if n % 2 == 0:
    upper_half = S[n // 2:]
else:
    upper_half = S[(n // 2) + 1:]
Q3 = median(upper_half)

# Print the interquartile range to 1 decimal place
print(f"{Q3 - Q1:.1f}")

    if name == 'main': n = int(input().strip()) values = list(map(int, input().rstrip().split())) freqs = list(map(int, input().rstrip().split()))

    # Ensure that the number of elements in S is equal to the sum of freqs
assert len(values) == len(freqs), "The length of values and freqs must be the same"
assert sum(freqs) <= 1000, "The sum of frequencies must be less than or equal to 1000"

interQuartile(values, freqs)

  • 21KN1A04C5
     + 0 comments

    python 3

    def interQuartile(values, freqs):
    l=[]
    for i in range(len(values)):
        for j in range(freqs[i]):
            l.append(values[i])
    l=sorted(l)
    if len(l)%2==0:
        print(float(statistics.median(l[len(l)//2:])-statistics.median(l[:len(l)//2])))
    else:
        print(float(statistics.median(l[(len(l)//2)+1:])-statistics.median(l[:len(l)//2])))

  • cjkang0601
     + 0 comments

    I can't pass test 5 and 6 can somebody help me plz

    def interQuartile(values, freqs):
    # Print your answer to 1 decimal place within this function
    new_lst = []
    for i in range(n):
        temp_freq = freqs[i]
        for j in range(temp_freq-1):
            val.append(val[i])
    new_lst = sorted(val)
    #print(new_lst)
    med = statistics.median(new_lst)
    print(med)
    Q1 =[]
    Q3 =[]
    for i in range(len(new_lst)):
        if new_lst[i] < med:
            Q1.append(new_lst[i])
        elif new_lst[i] > med:
            Q3.append(new_lst[i])
    Q1_med = statistics.median(Q1)
    Q3_med = statistics.median(Q3)
    print(Q1_med, Q3_med)
    return round(Q3_med - Q1_med, 1)