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    Thanks and visit my site.

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    def square_of_sum(arr, my_proc) sum = arr.reduce(0, &my_proc)

    sum ** 2 end

    sum_proc = proc { |a, b| a + b } input_array = [1, 2, 3]

    result = square_of_sum(input_array, sum_proc) for more information visit this site

    When run with the input array [1, 2, 3], the output will be 36.

    more info here

  • + 0 comments

    the ouput should be 36 and for more in depth knowledge and to edit visit capcut apk.

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    def square_of_sum(arr, my_proc) sum = arr.reduce(0, &my_proc)

    sum ** 2

    end

    sum_proc = proc { |a, b| a + b } input_array = [1, 2, 3]

    result = square_of_sum(input_array, sum_proc)

    When run with the input array [1, 2, 3], the output will be 36.

    more info here 

  • + 0 comments

    proc_square_number = proc {|proc_sum_array| proc_sum_array **2 }

    proc_sum_array = proc {|my_array| my_array.sum} my_array = gets.split().map(&:to_i)