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  1. Prepare
  2. Algorithms
  3. Implementation
  4. Repeated String
  5. Discussions

Repeated String

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3691 Discussions

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  • Arkeonn_
     + 0 comments

    JS solution :

    function repeatedString(s, n) {
    return ([...s.matchAll(/a/g)].length * Math.floor(n / s.length)) + ([...s.substring(0, (n % s.length)).matchAll(/a/g)].length);
}

  • alban_tyrex
     + 0 comments

    Here is my c++ solution, you can watch the explanation here : https://youtu.be/Vh5davsSkfA

    long ccount(string s) {
    return count(s.begin(), s.end(), 'a');
}

long repeatedString(string s, long n) {
    return (n / s.size()) * ccount(s) + ccount(s.substr(0, n % s.size()));
}

  • suleymanube
     + 0 comments

    Java 15

    class Result {

    private static final IntPredicate isA = c -> c == 'a';

    public static long repeatedString(String s, long n) {
      long times = n / s.length();
      long remainingChars = n % s.length();
      long count = s.chars().filter(isA).count();
      count*=times;  
      count += s.substring(0, (int) remainingChars).chars().filter(isA).count();  
      return count;
    }

}

  • pt023150
     + 0 comments

    java 8

    public static long repeatedString(String s, long n) {
    // Write your code here

    long count = 0;
    long div = n / s.length();
    long rem = n % s.length();

    if (n > s.length()) {
        for (int i = 0; i < s.length(); i++) {
            if (s.charAt(i) == 'a') {
                count++;
            }
        }
        if (div > 0) {
            count *= div;
        }
        if (rem > 0) {
            for (int i = 0; i < rem; i++) {
                if (s.charAt(i) == 'a') {
                    count++;
                }
            }
        }
    } else {
        for (int i = 0; i < n; i++) {
            if (s.charAt(i) == 'a') {
                count++;
            }
        }
    }
    return count;
}

  • david_padillac15
     + 0 comments

    Using JS

    function repeatedString(s, n) {
    if(s.length == 1){
        return n;
    }else{
        
        let count = 0;
        while(s.length < n){
            s = s + s;
        }
        let newString = s.substr(0, n);
        
        for (let partString of newString) {
            if (partString === 'a') {
                count++;
            }
        }

        return count;
        }
   
}