We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Mathematics
  3. Geometry
  4. Rectangular Game
  5. Discussions

Rectangular Game

Sort by

recency

|

40 Discussions

|

  • danielbrito
     + 0 comments

    In Kotlin, I got an overflow error in some test cases. I needed to change the return type for Long to make it pass.

  • sickfortea
     + 0 comments
    #include <iostream>
using namespace std;
void rectangularGame(int n)
{
    unsigned long long int a,b, minA, minB;
    for(int i=0; i<n; i++)
    {
        cin>>a>>b;
        if(i==0)
        {
            minA=a;
            minB=b;
        }
        if(a<minA)
        {
            minA=a;
        }
        if(b<minB)
        {
            minB=b;
        }
    }
    cout<<minA*minB;
}
int main()
{
    int n;
    cin>>n;
    rectangularGame(n);
    return 0;
}

  • sri555abhi
     + 0 comments

    Java :

    import java.util.Scanner;

public class Solution {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        int a = Integer.MAX_VALUE, b = Integer.MAX_VALUE;
        while (n-- > 0) {
            a = Math.min(a, sc.nextInt());
            b = Math.min(b, sc.nextInt());
        }
        
        System.out.println(1L * a * b);
    }
}

  • geddasaikrishna
     + 0 comments

    python code def solve(steps): x = [] y = [] for i in range(n): x.append(steps[i][0]) y.append(steps[i][1]) x1 = min(x) y1 = min(y) result = x1*y1 return result

  • murshid_islam
     + 0 comments

    My Python code, which passed all the test cases:

    def solve(steps):
    steps_tr = list(zip(*steps))  #list 'steps' transposed
    return min(steps_tr[0])*min(steps_tr[1])