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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Re.start() & Re.end()
  5. Discussions

Re.start() & Re.end()

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335 Discussions

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  • imam_alfaridzi
     + 0 comments

    Here's my code:

    from re import finditer
s, k = input().strip(), input().strip()
print(*[(m.start(1), m.end(1) - 1) for m in finditer(f'(?=({k}))', s)] or [(-1, -1)], sep='\n')

  • saifmhwh
     + 0 comments

    without using regex

    string_S = input()
string_k = input()

len_S = len(string_S)
len_k = len(string_k)

listed_script = []

for idS in range(len_S):
    if(idS+(len_k-1)<len_S):
        if ''.join([string_S[idS+idk] for idk in range(len_k)]) == string_k:
            listed_script.append((idS,idS+(len_k-1)))

if(len(listed_script)==0):
    listed_script.append((-1,-1))

for lsc in listed_script:
    print(lsc)

  • rejin_gunasekar1
     + 0 comments
    import re
S = input()
k = input()
R = list(re.finditer(f'(?={re.escape(k)})', S))
if R:
    for x in R:
        print((x.start(), x.start()+len(k)-1))
else:
    print((-1, -1))

  • achille_paschos
     + 0 comments

    Python 3 solution using only the exercise material, without any extra knowledge of re package.

    import re

    S = input() k = input()

    i = 0

    while i < len(S) - 1:

    m = re.search(k, S[i:])

if not m:
    if i ==0:
        print((-1, -1))
    break

elif m:
    print((m.start()+i, m.end()+i-1))
    i += m.end() - 1 if len(k)!=1 else m.end()

  • n4m774r_d
     + 0 comments
    import re
s,k = [input() for _ in range(2)]
p = r'(?=(%s))' % re.escape(k)
print("\n".join("(%s, %s)"%(match.start(1),match.end(1)-1) for match in re.finditer(p, s)) or "(-1, -1)")