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  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Group(), Groups() & Groupdict()
  5. Discussions

Group(), Groups() & Groupdict()

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245 Discussions

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  • imam_alfaridzi
     + 0 comments

    Here's my code:

    import re
print((lambda m: m and m.group(1) or -1)(re.search(r'([0-9a-zA-Z])\1+', input())))

  • eaaf123
     + 0 comments

    Intenté hacerlo así pero falla en el input 'init' y en el 'commit' cuando lo pruebo en un editor de código (VS code) funciona perfecto pero no pasa el test ¿A alguien mas le pasó lo mismo? import re cadena = str(input()) print((lambda m: m.group(1) if m else -1)(re.search(r'(\w)(?=\1)', cadena)))

  • rejin_gunasekar1
     + 0 comments
    import re
S = input()
m = re.search(r'([a-zA-Z0-9])\1+',S)
print(m.group(1) if m else -1)

  • ash_rabbi
     + 0 comments

    I managed to abuse the subscriptability of re.search:

    import re
s = input()
rx = re.compile(r"([a-zA-Z0-9])(?=\1)")
print(rx.search(s)[0] if rx.search(s) else -1)

  • n4m774r_d
     + 0 comments
    #Below Python 3.8 :
import re
s = input()    
print(s[re.search(r'([a-zA-Z\d])\1', s).start()]) if re.search(r'([a-zA-Z\d])\1', s) else print("-1")
#Since Python 3.8
print(s[match.start()]) if (match := re.search(r'([a-zA-Z\d])\1', s)) else print("-1")