We use cookies to ensure you have the best browsing experience on our website. Please read our cookie policy for more information about how we use cookies.
  1. Prepare
  2. Python
  3. Regex and Parsing
  4. Re.findall() & Re.finditer()
  5. Discussions

Re.findall() & Re.finditer()

  • yannickndl
     + 0 comments
    import re

pattern = r'(?<=[qwrtypsdfghjklzxcvbnmQWRTYPSDFGHJKLZXCVBNM])([aeiouAEIOU]{2,})(?=[qwrtypsdfghjklzxcvbnmQWRTYPSDFGHJKLZXCVBNM])'
results = list(re.finditer(pattern, input()))
print(*[x.group(1) for x in results] if results else [-1], sep="\n")