Re.findall() & Re.finditer()

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    import re
    k = []
    for i in re.finditer(r'(?<=[QWRTYPSDFGHJKLZXCVBNMqwrtypsdfghjklzxcvbnm])([aeiouAEIOU]{2,})(?=[QWRTYPSDFGHJKLZXCVBNMqwrtypsdfghjklzxcvbnm])', input()):
        print(i.group())
        k.append(i.group())
    if k == []:
        print(-1)