Discussion on String Formatting Challenge

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1 week ago+ 0 comments

def print_formatted(number):

w=len(str(bin(number))[2:])

for i in range(1,number+1):

    print(str(i).rjust(w,' '),oct(i)[2:].rjust(w,' '),hex(i)[2:].upper().rjust(w,' '), bin(i)[2:].rjust(w,' '))

2 weeks ago+ 0 comments

def print_formatted(number): wid = len(bin(number))-2 for i in range(1, number+1): print(f"{i:{wid}d} {i:{wid}o} {i:{wid}X} {i:{wid}b}") if name == 'main': n = int(input()) print_formatted(n)

2 weeks ago+ 0 comments

    m = 99
    n = min(m, m - (m - number))
    w = len(bin(n).removeprefix('0b'))
    for i in range(1, n + 1):
        print(
            str(int(i)).rjust(w),
            format(i, 'o').rjust(w),
            format(i, 'X').rjust(w),
            format(i, 'b').rjust(w)
        )

2 weeks ago+ 0 comments

def print_formatted(number):
    # your code goes here
    width = len(bin(number).removeprefix('0b'))
    methods = ['','oct','hex','bin']
    prefixs = ['','0o','0x','0b']

    for i in range(1,number+1):
        for j,k in zip(methods,prefixs):
            if j != '':
                y = eval(f"{j}({i}).removeprefix('{k}').upper()")
            else:
                y = str(i)
            print(y.rjust(width),end= " ")
        print()

3 weeks ago+ 0 comments

Script kiddie here. I'm thinking that I could replace removeprefix with some sort of replace syntax. (giving credit to Anisha for a clean script)

for a in range(number): #First we set up up a range w = len(format(number, 'b')) a=a+1 b = str(a) print(b.rjust(w), oct(a).removeprefix("0o").rjust(w),hex(a).removeprefix("0x").rjust(w).upper(),bin(a).removeprefix("0b").rjust(w))

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