Certainly! Let's discuss the provided Python code that takes an integer n as input and prints consecutive numbers from 1 to n without spaces.

if __name__ == '__main__':
    n = int(input())

    # Using a loop to print numbers from 1 to n without spaces
    for i in range(1, n + 1):
        print(i, end='')

    # Alternatively, you can use the join() method to concatenate the numbers
    # print(''.join(str(i) for i in range(1, n + 1)))

Explanation:

1. The script starts by checking if it is the main module (__name__ == '__main__'). This structure is often used to allow or prevent parts of code from being run when the modules are imported.

2. The integer n is read from the standard input (STDIN) using int(input()).

3. The code then uses a for loop to iterate through the range of numbers from 1 to n (inclusive).

4. Inside the loop, each number i is printed using the print(i, end='') statement. The end='' argument ensures that there is no space between the printed numbers.

5. Optionally, there is an alternative approach provided using the join() method. This method joins the numbers into a single string without spaces and then prints the result. The line is commented out in the code.

For example, if the input is 3, the output will be:

123

This code demonstrates a simple way to print consecutive numbers without spaces, and you can customize it for different input values.