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  1. Prepare
  2. Python
  3. Sets
  4. The Captain's Room
  5. Discussions

The Captain's Room

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1517 Discussions

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  • anw_g01
     + 0 comments

    Using sets specifcally:

    K = int(input())
s, ignore = set(), []
for room in map(int, input().split()):
    if room in s:
        s.remove(room)
        ignore.append(room)
    else:
        if room not in ignore:
            s.add(room)
print(s.pop())

  • luca_h94
     + 0 comments

    I should have used counter, but works too with defaultdict (used as counter)

    from collections import defaultdict

room_dict = defaultdict(list)

input()
room_numbers = input().split()

for room in room_numbers:
    room_dict[room].append("1")
    
for room, tourists in room_dict.items():
    if len(tourists) == 1:
        print(room)

  • parthkejriwal18
     + 0 comments

    k=int(input("enter: ")) n=tuple(map(int, input("enter: ").split())) for i in n: if n.count(i)>1: pass else: print(i)

  • luozhe2014
     + 0 comments

    from collections import Counter k = int(input()) s = Counter(map(int,input().split())) print(s.most_common()[-1][0])

  • ravikanth_kunch1
     + 0 comments

    My Approach is this; 

    inp = int(input())
list1 = list(map(int, input().split()))
dict = {}
for i in list1:
    if i not in dict:
        dict[i] = 1
    else:
        dict[i] += 1
for ind, ele in dict.items():
    if (ele < inp):
        print(ind)